Qt-interest Archive, March 2002
QString and latin1() question
Message 1 in thread
Hello All,
A search through the archives shows that this type of question has been asked
many times before but I still can't see the answer to my problem.
I have a function that takes a parameter like this:
function(char "command");
The problem is that I have to built up the command string from a character
array and a qstring along the following lines.
char string[25];
char string2 = {"some text "};
QString str = "here";
const char *string3 = str.latin1();
/* Build a command string */
sprintf(string,"%s %s","string2",string3);
If I now pass string to my function then the function fails (the function is
part of a library and not my own code).
I notice that the kdevelop debugger shows string like this:
"some text here\000\000\000"
If I code something like this then there isn't a problem, string = {"some
text here"}, and the debugger show this:
"some text here"
I have spent most of the day trying to sort this out and have tried may
variations without a usable result. I'm sure that the answer is a simple one.
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Message 2 in thread
> Hello All,
>
> A search through the archives shows that this type of question has been
asked
> many times before but I still can't see the answer to my problem.
>
> I have a function that takes a parameter like this:
> function(char "command");
>
Do you mean :
function(char * command);
> The problem is that I have to built up the command string from a character
> array and a qstring along the following lines.
>
> char string[25];
> char string2 = {"some text "};
>
Do you mean:
char *string2 = {"some text"};
> QString str = "here";
>
> const char *string3 = str.latin1();
>
> /* Build a command string */
> sprintf(string,"%s %s","string2",string3);
>
This should be OK.
> If I now pass string to my function then the function fails (the function
is
> part of a library and not my own code).
>
Put something like this as the first line of your function:
function(char *command)
{
qDebug("command = \"%s\" command length = %d", command,
strlen(command));
...
}
It should help you to figure out if the problem is in the construction of
the command string, or in the implementation of the function.
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