Qt-interest Archive, May 2008
How to iterate through widgets in QStackWidget?
Message 1 in thread
I have several different kind of panels stacked together inside one
QStackedWidget. I need to modify settings on all panels of one kind. My
problem is - I do not know how to get the real type of widget?
---------------------------
class PanelA : public QWidget {....};
class PanelB : public QWidget {....};
extern QStackedWidget *stack;
// stack is created and filled up somewhere with unknown number of PanelA
and PanelB widgets
for (int i; i<stack->count(); i++) {
QWidget *panel = stack->widget(i);
if ( panel ...... is of class PanelA ) { // how to do this condition???
PanelA *panelA = qobject_cast<PanelA*>(panel);
panelA->someFunctionOfA();
}
}
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Message 2 in thread
Hi,
Check
http://doc.trolltech.com/4.4/qobject.html#qobject_cast
qobject_cast, like dynamic_cast, will return 0 if the cast was
successful. Your code should look like this:
PanelA *panelA = qobject_cast<PanelA*>(panel);
if (panelA)
panelA->someFunctionOfA();
Cheers,
Ian.
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Message 3 in thread
Correction: They return 0 if the cast is UNsuccessful, of course.
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Message 4 in thread
Thank you.
"Ian Thomson" <Ian.Thomson@xxxxxxxxxx> wrote in message
news:482C6A8D.1090806@xxxxxxxxxxxxx
> Hi,
>
> Check
> http://doc.trolltech.com/4.4/qobject.html#qobject_cast
> qobject_cast, like dynamic_cast, will return 0 if the cast was successful.
> Your code should look like this:
>
> PanelA *panelA = qobject_cast<PanelA*>(panel);
> if (panelA)
> panelA->someFunctionOfA();
>
>
> Cheers,
> Ian.
>
> This email and any files transmitted with it are confidential and are
> intended solely for the use of the individual or entity to whom they are
> addressed. If you are not the original recipient or the person
> responsible for delivering the email to the intended recipient, be advised
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> prohibited. If you received this email in error, please immediately notify
> the sender and delete the original.
>
>
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